<code>
# 获取个数
#
# models.Tb1.objects.filter(name='seven').count()
# 大于，小于
#
# models.Tb1.objects.filter(id__gt=1) # 获取id大于1的值
# models.Tb1.objects.filter(id__lt=10) # 获取id小于10的值
# models.Tb1.objects.filter(id__lt=10, id__gt=1) # 获取id大于1 且 小于10的值
# in
#
# models.Tb1.objects.filter(id__in=[11, 22, 33]) # 获取id等于11、22、33的数据
# models.Tb1.objects.exclude(id__in=[11, 22, 33]) # not in
# contains
#
# models.Tb1.objects.filter(name__contains="ven")
# models.Tb1.objects.filter(name__icontains="ven") # icontains大小写不敏感
# models.Tb1.objects.exclude(name__icontains="ven")
# range
#
# models.Tb1.objects.filter(id__range=[1, 2]) # 范围bettwen and
# 其他类似
#
# startswith，istartswith, endswith, iendswith,
# order by
#
# models.Tb1.objects.filter(name='seven').order_by('id') # asc
# models.Tb1.objects.filter(name='seven').order_by('-id') # desc
# limit 、offset
#
# models.Tb1.objects.all()[10:20]
# group by
from django.db.models import Count, Min, Max, Sum
# models.Tb1.objects.filter(c1=1).values('id').annotate(c=Count('num'))
# SELECT "app01_tb1"."id", COUNT("app01_tb1"."num") AS "c" FROM "app01_tb1" WHERE "app01_tb1"."c1" = 1 GROUP BY "app01_tb1"."id"
</code>
用python计算昨天,今天,明天的日期
import datetime
today = datetime.date.today()
oneday = datetime.timedelta(days=1)
yesterday = today - oneday
tommorrow = today + oneday
