1.已知一个数字列表,求列表中心元素
list1 = [12, 34, 43, 54,42,51]
length = len(list1)
if length%2==1:
print(list1[int(length/2)])
else:
print(list1[int(length/2)-1],list1[int(length/2)])
2.已知一个数字列表,求所有元素和。
list1 = [12, 34, 43, 54,42,51]
sum = 0
for num in list1:
sum +=num
print(sum)
3.已知一个数字列表,输出所有奇数下标元素。
list1 = [12, 34, 43, 54,42,51]
print(list1[1::2]) #法1
4.已知一个数字列表,输出所有元素中,值为奇数的。
list1 = [12, 34, 43, 54,42,51]
num = int(len(list1))
for index in range(len(list1)):
if list1[index]%2==1:
print(list1[index], end=' ')
5.已知一个数字列表,将所有元素乘二。 例如:nums = [1, 2, 3, 4] —> nums = [2, 4, 6, 8]
print("=================================")
list1 = [12, 34, 43, 54,42,51]
for index in range(len(list1)):
print(list1[index]*2, end=' ')
6.有一个长度是10的列表,数组内有10个人名,要求去掉重复的, 例如:names = ['张三', '李四', '大黄', '张三'] -> names = ['张三', '李四', '大黄']
names = ['张三', '李四', '大黄', '张三']
names2 = []
for i in range(len(names)):
print(names[i])
if names[i] not in names2:
names2.append(names[i])
print(names2)
7.已经一个数字列表(数字大小在0~6535之间), 将列表转换成数字对应的字符列表,例如: list1 = [97, 98, 99] -> list1 = ['a', 'b', 'c']
list1 = [97, 98, 99]
list2 = []
for i in range(len(list1)):
list2.append(chr(list1[i]))
print(list2)
8.用一个列表来保存一个节目的所有分数,求平均分数(去掉一个最高分,去掉一个最低分,求最后得分)
grades = [23,12,45,31,56,87,21,88]
grades2 = grades[:]
sum = 0
grades.remove(max(grades[:]))
grades.remove(min(grades[:]))
# print(grades)
# print(grades2)
for grade in grades:
sum += grade
print(sum/int(len(grades)))
9.有两个列表A和B,使用列表C来获取两个列表中公共的元素例如: A = [1, 'a', 4,'c', 90] B = ['a', 8, 'j','c', 1] --> C = [1, 'a']
list_a = [1, 'a', 4, 'c',90]
list_b = ['a', 8, 'j', 1,'c']
list_c = []
for a in list_a:
if a in list_b:
list_c.append(a)
print(list_c)
10.有一个数字列表,获取这个列表中的最大值.(注意: 不能使用max函数),例如: nums = [19, 89, 90, 600, 1] —> 600
nums = [19, 89, 90, 600, 1]
for i in range(len(nums)):
for j in range(len(nums)):
if nums[i]>nums[j]:
max = nums[i]
print(max)
11.获取列表中出现次数最多的元素 例如:nums = [1, 2, 3,1,4,2,1,3,7,3,3] —> 打印:3
nums = [1, 2, 3,1,4,2,1,3,7,3,3]
temp = []
max_item = 0
for num in nums:
# print(num, nums2.count(num))
t = nums2.count(num)
temp.append(t)
if max_item < max(temp):
max_item = max(temp)
max_num = num
print(max_num)