Merge Sort

Sort List

Sort a linked list in O(n log n) time using constant space complexity.
Example 1:
Input: 4->2->1->3
Output: 1->2->3->4
Example 2:
Input: -1->5->3->4->0
Output: -1->0->3->4->5

public class Solution {
  
  public ListNode sortList(ListNode head) {
    if (head == null || head.next == null)
      return head;
        
    // step 1. cut the list to two halves
    ListNode prev = null, slow = head, fast = head;
    
    while (fast != null && fast.next != null) {
      prev = slow;
      slow = slow.next;
      fast = fast.next.next;
    }
    
    prev.next = null;
    
    // step 2. sort each half
    ListNode l1 = sortList(head);
    ListNode l2 = sortList(slow);
    
    // step 3. merge l1 and l2
    return merge(l1, l2);
  }
  
  ListNode merge(ListNode l1, ListNode l2) {
    ListNode l = new ListNode(0), p = l;
    
    while (l1 != null && l2 != null) {
      if (l1.val < l2.val) {
        p.next = l1;
        l1 = l1.next;
      } else {
        p.next = l2;
        l2 = l2.next;
      }
      p = p.next;
    }
    
    if (l1 != null)
      p.next = l1;
    
    if (l2 != null)
      p.next = l2;
    
    return l.next;
  }

}

注意：用两个指针来把链表分成两半；归并排序；