笨办法学Python ex35

分支和函数

• 输入：

# -*- coding: utf-8 -*-

from sys import exit

def gold_room():
    print "This room is full of gold. How much do you take?"
    
    choice = raw_input("> ")
    if "0"  in choice or "1" in choice:
        how_much = int(choice)
    else:
        dead("Man, learn to type a number.")
        
    if how_much < 50:
        print "Nice, you're not greedy, you win!"
        exit(0)
    else:
        dead("You greedy bastard!")

def bear_room():
    print "There is a bear here."
    print "The bear has a bunch of honey."
    print "The fat bear is in front of another door."
    print "How are you going to move the bear?"
    bear_moved = False
    
    while True:
        choice = raw_input("> ")
        
        if choice == "take honey":
            dead("The bear looks at you then slaps your face off.")
        elif choice == "taunt bear" and not bear_moved:
            print "The bear has moved from the door. You can go through it now."
            bear_moved = True
        elif choice == "taunt bear" and bear_moved:
            dead("The bear gets pissed off and chews your leg off.")
        elif choice == "open door" and bear_moved:
            gold_room()
        else:
            print "I got no idea what that means."

def cthulhu_room():
    print "Here you see the great evil Cthulhu."
    print "He, it, whatever stares at you and you go insane."
    print "Do you flee for your life or eat your head?"
    
    choice = raw_input("> ")
    
    if "flee" in choice:
        start()
    elif "head" in choice:
        head("Well that was tasty!")
    else:
        cthulhu_room()

def dead(why):
    print why, "Good job!"
    exit(0)
    
def start():
    print "You are in a dark room."
    print "There is a door to your righr and left."
    print "Which one do you take?"
    
    choice = raw_input("> ")
    
    if choice == "left":
        bear_room()
    elif choice == "right":
        cthulhu_room()
    else:
        dead("You stumble around the room until you starve.")
        
start()

• 运行：

  
  

附加题

• 这个 gold_room 游戏使用了奇怪的方式让你键入数字。这种方式会导致什么样的 bug？ 你可以用比检查 0、1 更好的方式判断输入是否是数字吗？int() 这个函数可以给你一些头绪。

这里用了一个判断输入的数字是否含1或者0来检查是否输入的是数字，很明显的bug就是避开0和1的数字会被当作非数字来执行，例如输入55

》》》初步的想法，检测数字的话，用四则运算最直接，比如15/15=1，于是代码改为：

def gold_room():
    print "This room is full of gold. How much do you take?"
    choice = raw_input("> ")
    if int(choice) / int(choice) == 1:
        how_much = int(choice)
    else:
        dead("Man, learn to type a number.")
        
    if how_much < 50:
        print "Nice, you're not greedy, you win!"
        exit(0)
    else:
        dead("You greedy bastard!")