Problem
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example:
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Solution 1
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
for(int i=0;i<n;i++){
nums1[i+m]=nums2[i];
}
sort(nums1.begin(),nums1.end());
}
};
static auto speedup = [](){
ios::sync_with_stdio(false);
cin.tie(nullptr);
return nullptr;
}();
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