平面排列(非递归实现)
给定一个列表,该列表中的每个要素要么是个列表,要么是整数。将其变成一个只包含整数的简单列表。
样例
给定 [1,2,[1,2]],返回 [1,2,1,2]。
给定 [4,[3,[2,[1]]]],返回 [4,3,2,1]。
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer,
* // rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds,
* // if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds,
* // if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class Solution {
// @param nestedList a list of NestedInteger
// @return a list of integer
public List<Integer> flatten(List<NestedInteger> nestedList) {
// Write your code here
List<Integer> data = new ArrayList<Integer>();
if(nestedList == null){
return null;
}
for(int k = 0; k < nestedList.size(); k++){
if(nestedList.get(k).getInteger() != null){
data.add(nestedList.get(k).getInteger());
}else{
Queue<NestedInteger> list = new LinkedList();
list.offer(nestedList.get(k));
boolean b = true;
while(b){
int size = list.size();
b = false;
for(int i = 0; i < size; i++){
NestedInteger vo = list.poll();
if(vo.getInteger() != null){
// data.add(vo.getInteger());
list.offer(vo);
}else{
b = true;
for(int j = 0; j < vo.getList().size(); j++){
list.offer(vo.getList().get(j));
}
}
}
}
int size = list.size();
for(int i = 0; i < size; i++){
NestedInteger vo = list.poll();
data.add(vo.getInteger());
}
}
}
return data;
}
}