刚开始学习python的时候，对有关args,kwargs,和*的使用感到很困惑。相信对此感到疑惑的人也有很多。我打算通过这个帖子来排解这个疑惑(希望能减少疑惑)。
- *args表示任何多个无名参数，它是一个tuple
- **kwargs:传入的字典，就如：a=1,传入键值
传入元组,args表示成一个元组
def param_tuple(*args):
print(type(args))
print(args)
for value in args:
print(value)
for key,value in enumerate(args):
print("{0}->{1}".format(key,value))
param_tuple(1,2,43)
输出结果为：
<class 'tuple'>
(1, 2, 43)
1
2
43
0->1
1->2
2->43
传入元组给**kwargs会报错
def param_tuple(**kargs):
print(type(kargs))
print(kargs)
param_tuple(1,2,43)
输出结果为：
发生异常: TypeError
param_tuple() takes 0 positional arguments but 3 were given
参数中传入字典, **kwargs表示成一个字典
def param_tuple(**kargs):
print(type(kargs))
print(kargs)
for key,value in enumerate(kargs):
print("{0}->{1}".format(key,value))
param_tuple(a = 1, b = 2, c = 43)
输出结果为：
<class 'dict'>
{'a': 1, 'b': 2, 'c': 43}
0->a
1->b
2->c
函数的参数中混用tuple和dic
def param_tuple_dic(*args, **kwargs):
print(type(args))
print(type(kwargs))
print(args)
print(kwargs)
for value in args:
print(value)
for key ,value in kwargs.items():
print("{0}==>{1}".format(key,value))
param_tuple_dic("1","2","43", a = 1, b = 2, c = 43)
输出结果为：
<class 'tuple'>
<class 'dict'>
('1', '2', '43')
{'a': 1, 'b': 2, 'c': 43}
1
2
43
a==>1
b==>2
c==>43
