1. 一句代码截屏
UIView *view = [self.view snapshotViewAfterScreenUpdates:YES];
2. UIGraphics
- (UIImage *)screenShot {
UIGraphicsBeginImageContextWithOptions(CGSizeMake(SCREEN_WIDTH, SCREEN_HEIGHT), NO, 0.0);
[self.view.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *screenShotImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return screenShotImage;
}
3. 还有就是之前一个大佬写的给webview截长图的
其实就是利用webView的contentSize和webView中的scrollView的contentOffset, 多次截屏, 最后拼接到一张长图上
- (UIImage *)imageForWebView
{
// 1.获取WebView的宽高
CGSize boundsSize = self.bounds.size;
CGFloat boundsWidth = boundsSize.width;
CGFloat boundsHeight = boundsSize.height;
// 2.获取contentSize
CGSize contentSize = self.scrollView.contentSize;
CGFloat contentHeight = contentSize.height;
// 3.保存原始偏移量,便于截图后复位
CGPoint offset = self.scrollView.contentOffset;
// 4.设置最初的偏移量为(0,0);
[self.scrollView setContentOffset:CGPointMake(0, 0)];
NSMutableArray *images = [NSMutableArray array];
while (contentHeight > 0) {
// 5.获取CGContext 5.获取CGContext
UIGraphicsBeginImageContextWithOptions(boundsSize, NO, 0.0);
CGContextRef ctx = UIGraphicsGetCurrentContext();
// 6.渲染要截取的区域
[self.layer renderInContext:ctx];
UIImage *image = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
// 7.截取的图片保存起来
[images addObject:image];
CGFloat offsetY = self.scrollView.contentOffset.y;
[self.scrollView setContentOffset:CGPointMake(0, offsetY + boundsHeight)];
contentHeight -= boundsHeight;
}
// 8 webView 恢复到之前的显示区域
[self.scrollView setContentOffset:offset];
CGFloat scale = [UIScreen mainScreen].scale;
CGSize imageSize = CGSizeMake(contentSize.width * scale,
contentSize.height * scale);
// 9.根据设备的分辨率重新绘制、拼接成完整清晰图片
UIGraphicsBeginImageContext(imageSize);
[images enumerateObjectsUsingBlock:^(UIImage *image, NSUInteger idx, BOOL *stop) {
[image drawInRect:CGRectMake(0,scale * boundsHeight * idx,scale * boundsWidth,scale * boundsHeight)];
}];
UIImage *fullImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return fullImage;
}