python路径拼接os.path.join()函数的用法

os.path.join()函数：连接两个或更多的路径名组件

1.如果各组件名首字母不包含’/’，则函数会自动加上

2.如果有一个组件是一个绝对路径，则在它之前的所有组件均会被舍弃

3.如果最后一个组件为空，则生成的路径以一个’/’分隔符结尾

Demo1

import os

Path1 = 'home'
Path2 = 'develop'
Path3 = 'code'

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)

输出

Path10 = homedevelopcode
Path20 = home\develop\code

--------------------------------------------------------------

Demo2

import os

Path1 = '/home'
Path2 = 'develop'
Path3 = 'code'

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)
输出

Path10 = /homedevelopcode
Path20 = /home\develop\code

--------------------------------------------------------------

Demo3

import os

Path1 = 'home'
Path2 = '/develop'
Path3 = 'code'

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)

输出

Path10 = home/developcode
Path20 = /develop\code

--------------------------------------------------------------

Demo4

import os

Path1 = 'home'
Path2 = 'develop'
Path3 = '/code'

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20 )

输出

Path10 = homedevelop/code
Path20 = /code

转：https://blog.csdn.net/hduxiejun/article/details/80289476

获取路径方法

import os
 
print '***获取当前目录***'
print os.getcwd()   #获取的是调用文件的当前路径，不是该脚本的当前路径
print os.path.abspath(os.path.dirname(__file__)) #获取该脚本的当前路径，需要调用的时候要用这个方法才能找对正确的路径，用os.getcwd()方法会找到错误路径
# __file__ 为当前文件, 若果在ide中运行此行会报错,可改为 #d = path.dirname('.') 
# 但是改为.后，就是获得当前目录，接着使用dirname函数访问上级目录
print '***获取上级目录***'
print os.path.abspath(os.path.dirname(os.path.dirname(__file__)))
print os.path.abspath(os.path.dirname(os.getcwd()))
print os.path.abspath(os.path.join(os.getcwd(), ".."))
print '***获取上上级目录***'
print os.path.abspath(os.path.join(os.getcwd(), "../.."))