方法一:
逻辑:将需要改变键名的键值对赋值给一个新的键值对,然后将旧的键值对删除
var arr = ({name:'张三', age: 44}, {name:'李四', age: 88})
newarr = arr
for( let i=0;i<arr.length;i++ ){
newarr[i].nam = arr[i].name['name']
detele newarr[i].name
}
方法二: // 推荐使用
逻辑:map函数
var arr = ({name:'张三', age: 44}, {name:'李四', age: 88})
newarr = []
arr.map(a => {
let obj = {}
obj.nam = a.name
obj.age = a.age
newarr.push(obj)
return a
})