1.put方法
1.把存入元素用hashcode产生hash值然后用hash%table.length取余产生数组下标
2.当插入元素hash相同时，存入数组某个元素的链表中，
从头部存入。然后把新插入的元素移动一下，使得get获得值变成最后put的元素
HashMap中的put方法
//阈值（java1.8中和1.7中不太一样）
this.threshold = tableSizeFor(initialCapacity);
//返回大于等于传入数字的二的次方数
static final int tableSizeFor(int cap) {
int n = cap - 1;//减一的原因是担心直接输入二的次方数，类似4，8，16
n |= n >>> 1;//二进制右移一位进行或运算
n |= n >>> 2;//右移最大只有16位是因为int类型最大32位
n |= n >>> 4;
n |= n >>> 8;
n |= n >>> 16;
//最后得到的数字应该全部是一
return (n < 0) ? 1 : (n >= MAXIMUM_CAPACITY) ? MAXIMUM_CAPACITY : n + 1;
//判断是否大于最大容量，不是的话加1就是结果
}
//8bit(位)=1Byte(字节)一位在内存中有一个格子
//1024Byte(字节)=1KB
//1024KB=1MB
//1024MB=1GB
//异或运算，相同为0不同为1
//put方法第一步：初始化tab
n = (tab = resize()).length;
//第二步算出当前插入元素的数组下标，看这个下标的内部元素
//是否为空，如果为空就new Node
if ((p = tab[i = (n - 1) & hash]) == null)
//如果不是空，先新建两个变量，就执行以下三个判断
Node<K,V> e; K k;
//第一步判断当前结点key和插入的key是否一致，一致就把当前结点p赋值e
if (p.hash == hash &&
((k = p.key) == key || (key != null && key.equals(k))))
e = p;
//否则的话判断p结点的类型是否是一个TreeNode
//红黑树方法
//插入红黑树
else if (p instanceof TreeNode)
e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
//否则的话就走链表类型
for (int binCount = 0; ; ++binCount) {
//如果当前结点的下一个结点是空，
if ((e = p.next) == null) {
p.next = newNode(hash, key, value, null);
//判断当前链表处的结点数量是否大于TREEIFY_THRESHOLD（8）大于的话就转换为一个红黑树，当第九个来的时候树化
if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
treeifyBin(tab, hash);
break;
}
//遍历链表判断当前结点是否找到，找到停止循环，把e赋值给p
if (e.hash == hash &&((k = e.key) == key || (key != null && key.equals(k))))
break;
p = e;
}
//如果已经存在key，则把以前的value替换成新value，并把老的值return回去
if (e != null) {
V oldValue = e.value;
if (!onlyIfAbsent || oldValue == null)e.value = value;
afterNodeAccess(e);
return oldValue;
}
//上面的代码进行完还没有return就修改次数加一，判断是否需要扩容
++modCount;
if (++size > threshold)
resize();
afterNodeInsertion(evict);
return null;
treeifyBin(tab, hash)转红黑树代码
final void treeifyBin(Node<K,V>[] tab, int hash) {
int n, index; Node<K,V> e;
//判断是否为空，或者是否小于64，MIN_TREEIFY_CAPACITY值为64，扩容或者初始化
if (tab == null || (n = tab.length) < MIN_TREEIFY_CAPACITY)
resize();//重新计算下标，减短链表
//判断当前数组下标是否为空，不为空树化
else if ((e = tab[index = (n - 1) & hash]) != null) {
//树化代码
//遍历链表的每一个元素
TreeNode<K,V> hd = null, tl = null;
do {
//new 一个treeNode结点
TreeNode<K,V> p = replacementTreeNode(e, null);
//然后把链表变成一个双向链表！！！！！！！
if (tl == null)
hd = p;
else {
p.prev = tl;
tl.next = p;
}
tl = p;
} while ((e = e.next) != null);
//把双向链表变为红黑树
if ((tab[index] = hd) != null)
hd.treeify(tab);
}
}
//new 一个treeNode
TreeNode<K,V> replacementTreeNode(Node<K,V> p, Node<K,V> next) {
return new TreeNode<>(p.hash, p.key, p.value, next);
}
关于treeNode解释
红黑树里面的一个结点
TreeNode<K,V> parent; // 父节点
TreeNode<K,V> left;
TreeNode<K,V> right;
TreeNode<K,V> prev; //双向链表
boolean red;
treeify(tab)为TreeNode内的一个方法
final void treeify(Node<K,V>[] tab) {
TreeNode<K,V> root = null;
//遍历链表
for (TreeNode<K,V> x = this, next; x != null; x = next) {
next = (TreeNode<K,V>)x.next;
x.left = x.right = null;
//判断root是否为空，为空把第一个结点变成头结点
if (root == null) {
x.parent = null;
x.red = false;
root = x;
}
else {
K k = x.key;
int h = x.hash;
Class<?> kc = null;
for (TreeNode<K,V> p = root;;) {
int dir, ph;
K pk = p.key;
if ((ph = p.hash) > h)
dir = -1;
else if (ph < h)
dir = 1;
else if ((kc == null &&
(kc = comparableClassFor(k)) == null) ||
(dir = compareComparables(kc, k, pk)) == 0)
dir = tieBreakOrder(k, pk);
TreeNode<K,V> xp = p;
if ((p = (dir <= 0) ? p.left : p.right) == null) {
x.parent = xp;
if (dir <= 0)
xp.left = x;
else
xp.right = x;
//把x结点插入红黑树，调整红黑树
root = balanceInsertion(root, x);
break;
}
}
}
}
//至此形成一个红黑树，下面把根节点移动到散列表位置
//备注：转换过程保留双向链表，规则，红黑树的根节点是双向链表的头结点，所以使用双向链表
moveRootToFront(tab, root);
}
获得一个对象的hash值方法
identityHashCode()
插入红黑树方法putTreeVal
e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
final TreeNode<K,V> putTreeVal(HashMap<K,V> map, Node<K,V>[] tab,
int h, K k, V v) {
Class<?> kc = null;
boolean searched = false;
TreeNode<K,V> root = (parent != null) ? root() : this;
for (TreeNode<K,V> p = root;;) {
int dir, ph; K pk;
if ((ph = p.hash) > h)
dir = -1;
else if (ph < h)
dir = 1;
else if ((pk = p.key) == k || (k != null && k.equals(pk)))
return p;
else if ((kc == null &&
(kc = comparableClassFor(k)) == null) ||
(dir = compareComparables(kc, k, pk)) == 0) {
if (!searched) {
TreeNode<K,V> q, ch;
searched = true;
if (((ch = p.left) != null &&
(q = ch.find(h, k, kc)) != null) ||
((ch = p.right) != null &&
(q = ch.find(h, k, kc)) != null))
return q;
}
dir = tieBreakOrder(k, pk);
}
TreeNode<K,V> xp = p;
if ((p = (dir <= 0) ? p.left : p.right) == null) {
Node<K,V> xpn = xp.next;
TreeNode<K,V> x = map.newTreeNode(h, k, v, xpn);
if (dir <= 0)
xp.left = x;
else
xp.right = x;
xp.next = x;
x.parent = x.prev = xp;
if (xpn != null)
((TreeNode<K,V>)xpn).prev = x;
moveRootToFront(tab, balanceInsertion(root, x));
return null;
}
}
}
扩容resize
//size代表当前map数据总量
if (++size > threshold)
resize();
afterNodeInsertion(evict);
下面方法包括扩容和初始化
final Node<K,V>[] resize() {
Node<K,V>[] oldTab = table;
int oldCap = (oldTab == null) ? 0 : oldTab.length;
int oldThr = threshold;
int newCap, newThr = 0;
if (oldCap > 0) {
if (oldCap >= MAXIMUM_CAPACITY) {
threshold = Integer.MAX_VALUE;
return oldTab;
}
else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
oldCap >= DEFAULT_INITIAL_CAPACITY)
newThr = oldThr << 1; // double threshold
}
else if (oldThr > 0) // initial capacity was placed in threshold
newCap = oldThr;
else { // zero initial threshold signifies using defaults
newCap = DEFAULT_INITIAL_CAPACITY;
newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
}
if (newThr == 0) {
float ft = (float)newCap * loadFactor;
newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
(int)ft : Integer.MAX_VALUE);
}
threshold = newThr;
@SuppressWarnings({"rawtypes","unchecked"})
Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
table = newTab;
//以上内容均为数组初始化，以下内容为扩容
if (oldTab != null) {
//遍历老数组上面的每个元素
for (int j = 0; j < oldCap; ++j) {
Node<K,V> e;
if ((e = oldTab[j]) != null) {
oldTab[j] = null;
//表示当前数组位置元素只有一个元素
if (e.next == null)
//把e元素放入新数组中（计算新数组下标）
newTab[e.hash & (newCap - 1)] = e;
//如果e是红黑树里面的一个结点
else if (e instanceof TreeNode)
//红黑树扩容，传hashmap自己，和新数组，和老数组当前位置数组元素，和老数组
((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
//如果为链表，进行扩容
else { // preserve order
Node<K,V> loHead = null, loTail = null;
Node<K,V> hiHead = null, hiTail = null;
Node<K,V> next;
//遍历链表每个元素
do {
next = e.next;
//用当前结点的hash值和老数组对象的hash值进行与运算，
//只有两个结果，0/1，把所有链表元素遍历一遍，就将一个长链表拆分成两个链表
if ((e.hash & oldCap) == 0) {
if (loTail == null)//上面运算等于0的就是low低位数组
loHead = e;
else
loTail.next = e;
loTail = e;
}
else {
if (hiTail == null)//等于1就是高位数组
hiHead = e;
else
hiTail.next = e;
hiTail = e;
}
} while ((e = next) != null);
if (loTail != null) {
//遍历结束
loTail.next = null;
newTab[j] = loHead;//把low组放进前面
}
if (hiTail != null) {
hiTail.next = null;
newTab[j + oldCap] = hiHead;//把high组接着放
}
}
}
}
}
return newTab;
}
//红黑树扩容将树箱中的节点拆分为上下树箱，
//或取消树化（如果现在太小）。仅从调整大小调用，bit为原数组大小
final void split(HashMap<K,V> map, Node<K,V>[] tab, int index, int bit) {
TreeNode<K,V> b = this;
// Relink into lo and hi lists, preserving order
//新建两个子树
TreeNode<K,V> loHead = null, loTail = null;
TreeNode<K,V> hiHead = null, hiTail = null;
int lc = 0, hc = 0;
for (TreeNode<K,V> e = b, next; e != null; e = next) {
next = (TreeNode<K,V>)e.next;
e.next = null;
if ((e.hash & bit) == 0) {
if ((e.prev = loTail) == null)
loHead = e;
else
loTail.next = e;
loTail = e;
++lc;
}
else {
if ((e.prev = hiTail) == null)
hiHead = e;
else
hiTail.next = e;
hiTail = e;
++hc;
}
}
if (loHead != null)
//如果低位子树元素个数小于六个，进行把树转化为单向链表
if (lc <= UNTREEIFY_THRESHOLD)
tab[index] = loHead.untreeify(map);
else {
tab[index] = loHead;
//如果高位数组如果是空，不需要调整树，以前的就行
//如果高位数组为空，则需要重新树化，调整为平衡二叉树
if (hiHead != null) // (else is already treeified)
loHead.treeify(tab);
}
}
if (hiHead != null) {
//如果高位子树元素个数小于六个，进行把树转化为链表
if (hc <= UNTREEIFY_THRESHOLD)
tab[index + bit] = hiHead.untreeify(map);
else {
tab[index + bit] = hiHead;
if (loHead != null)
hiHead.treeify(tab);
}
}
}
//整个源码
final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
boolean evict) {
Node<K,V>[] tab; Node<K,V> p; int n, i;
if ((tab = table) == null || (n = tab.length) == 0)
n = (tab = resize()).length;
if ((p = tab[i = (n - 1) & hash]) == null)
tab[i] = newNode(hash, key, value, null);
else {
Node<K,V> e; K k;
if (p.hash == hash &&
((k = p.key) == key || (key != null && key.equals(k))))
e = p;
else if (p instanceof TreeNode)
e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
else {
for (int binCount = 0; ; ++binCount) {
if ((e = p.next) == null) {
p.next = newNode(hash, key, value, null);
if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
treeifyBin(tab, hash);
break;
}
if (e.hash == hash &&
((k = e.key) == key || (key != null && key.equals(k))))
break;
p = e;
}
}
if (e != null) { // existing mapping for key
V oldValue = e.value;
if (!onlyIfAbsent || oldValue == null)
e.value = value;
afterNodeAccess(e);
return oldValue;
}
}
++modCount;
if (++size > threshold)
resize();
afterNodeInsertion(evict);
return null;
}
2.get方法
public V get(Object key) {
Node<K,V> e;
//三元运算
return (e = getNode(hash(key), key)) == null ? null : e.value;
}
final Node<K,V> getNode(int hash, Object key) {
Node<K,V>[] tab; Node<K,V> first, e; int n; K k;
if ((tab = table) != null && (n = tab.length) > 0 &&
//查找需要查找的key在散列表的数组中的位置，并且把当前数组元素赋给first，判断这个位置元素是否为空
//(n-1) & hash 作用是计算数组索引下标
(first = tab[(n - 1) & hash]) != null) {
//检验大数组第一个结点的key
if (first.hash == hash && // always check first node
((k = first.key) == key || (key != null && key.equals(k))))
return first;
if ((e = first.next) != null) {
//第二个结点，如果是二叉树就调用地下方法
if (first instanceof TreeNode)
return ((TreeNode<K,V>)first).getTreeNode(hash, key);
//如果不是，树，那就是一个链表，然后遍历链表判断key和哪个相等
do {
if (e.hash == hash &&
((k = e.key) == key || (key != null && key.equals(k))))
return e;
} while ((e = e.next) != null);
}
}
return null;
}
