LeetCode-344(反转字符串)

v1

• 元素折中反转 时间O(n/2) 空间O(1)

class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        mid = s.__len__() >> 1
        
        for i in range(mid):
            s[i], s[(-i)-1] = s[(-i)-1], s[i]