Leetcode 1. Two Sum

Python 3 实现:

源代码已上传 Github,持续更新。

"""
1. Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:
Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
"""

class Solution:

    def twoSum(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: List[int]
        """

        dic = {}
        for i in range(len(nums)):
            if nums[i] in dic:
                return [dic[nums[i]], i]
            else:
                dic[target - nums[i]] = i


if __name__ == '__main__':
    solution = Solution()
    print(solution.twoSum([3, 2, 4], 6))
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