题目：输出斐波那契数列的第n项
方法一：
# -*- coding:utf-8 -*-
def fib(n):
a,b = 1,1
for i in range(n-1):
a,b = b,a+b
return a
print "fib(10)=",fib(10)
方法二：
# -*- coding:utf-8 -*-
def fib(n):
if n == 1 or n == 2:
return 1
else:
return fib(n - 1) + fib(n - 2)
print fib(10)
拓展：输入斐波那契数列的前n项：
# -*- coding:utf-8 -*-
def fib(n):
if n == 1:
return [1]
if n == 2:
return [1,1]
fibs = [1,1]
for i in range(2,n):
fibs.append(fibs[-1] + fibs[-2])
return fibs
print fib(10)
