字符串的介绍
- 字符串在任何的开发中使用都是非常频繁的
- OC和Swift中字符串的区别
- 在OC中字符串类型时NSString,在Swift中字符串类型是String
- OC中字符串@"",Swift中字符串""
- 使用
String
的原因
-
String
是一个结构体,性能更高
-
NSString
是一个 OC
对象,性能略差
-
String
支持直接遍历
-
Swift
提供了 String
和 NSString
之间的无缝转换
字符串的定义
// 1> 定义不可变字符串 : 使用let修饰
let str : String = "hello swift"
// str = "hello Objective-C" 错误写法
// 2> 定义可变字符串 : 使用var修饰
var strM : String = "hello world"
strM = "hello china"
字符串的使用
获取字符串的长度
let count = str.characters.count
字符串拼接
let str1 = "Hello"
let str2 = "World"
let str3 = str1 + str2
let name = "why"
let age = 18
let info = "my name is \(name), age is \(age)"
let min = 3
let second = 4
let time = String(format: "%02d:%02d", arguments: [min, second])
字符串的截取
- Swift中提供了特殊的截取方式
- 简单的方式是将String转成NSString来使用
let urlString = "www.520it.com"
// Swift中通过 as 关键字可以将String类型转成NSString的类型
let header1 = (urlString as NSString).substring(to: 3)
let footer1 = (urlString as NSString).substring(from: 10)
let range1 = NSRange(location: 4, length: 5)
let middle1 = (urlString as NSString).substring(with: range1)
let urlString = "www.520it.com"
let headerIndex = urlString.index(urlString.startIndex, offsetBy: 3)
let header2 = urlString.substring(to: headerIndex)
let footerIndex = urlString.index(urlString.endIndex, offsetBy: -3)
let footer2 = urlString.substring(from: footerIndex)
let startIndex = urlString.index(urlString.startIndex, offsetBy: 4)
let endIndex = urlString.index(urlString.startIndex, offsetBy: 9)
let range2 = Range(startIndex..<endIndex)
let middle2 = urlString.substring(with: range2)
- 两个字符串的比较
在 Swift 中字符串的比较方式有三种
// 直接比较,Swift中字符串遵循 Sequence 协议,都可以这样比较
"xiaoyou".elementsEqual("晓友")
// 遍历字符串,比较内部单个字符
for index in 0..<userAnswer.length {
// 比较对应位置的word 是否相同
if userAnswer.substring(with: NSMakeRange(index, 1)).compare(answer.substring(with: NSMakeRange(index, 1))) == ComparisonResult.orderedSame {
print("-----same")
}else{
print("-----不一样,需要替换")
}
// 比较对应位置的 Character 是否相同
let userA = userAnswer.character(at: index)
let corrA = answer.character(at: index)
if userA == corrA {
print("\(userA)+++++++same")
}else{
print("\(userA)+\(corrA)++++++不一样,需要替换")
}
}