输入数据统计

输入一些整数，求出他们的最小值，最大值，平均值（保留三位小数）。保证输入数字不超过1000

方案一

#include <iostream>
using namespace std;

int main(int argc, char const *argv[])
{
    int i = 0;
    int max = 0;
    int min = 0;
    int sum = 0;
    int n = 0;
    while (scanf("%d", &i) == 1)
    {
        n++;
        if (n == 1)
        {
            min = i;
            max = i;
        }

        if (i > max)
            max = i;
        if (i < min)
            min = i;
        sum += i;
    }
    printf("最大值：%d，最小值 %d，平均值：%.3f", max, min, float(sum / n));
    return 0;
}

弱点 单次循环输入，操作性太弱。并且程序结束出口繁琐。

方案二

#include <iostream>
using namespace std;
#define INF 100000000

int main(int argc, char const *argv[])
{
    FILE *fin, *fout;
    fin = fopen("data.in", "rb");
    fout = fopen("data.out", "wb");
    int x, n = 0, min = INF, max = -INF, s = 0;
    while (fscanf(fin, "%d", &x) == 1)
    {
        s+=x;
        if (x<min) min = x;
        if (x>max) max = x;
        n++;
    }
    fprintf(fout,"d% %d %.3f\n",min,max,(double)s/n);
    fclose(fin);
    fclose(fout);
    return 0;
}