12.获取所有部门中当前员工薪水最高的相关信息

获取所有部门中当前员工薪水最高的相关信息，给出dept_no, emp_no以及其对应的salary

CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));

CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

解析：考察分组

select de.dept_no, sa.emp_no, max(sa.salary) as salary
from dept_emp as de, salaries as sa
where de.emp_no = sa.emp_no
and de.to_date = '9999-01-01'
and sa.to_date = '9999-01-01'
group by dept_no