Given 2 int values greater than 0, return whichever value is nearest to 21 without going over. Return 0 if they both go over.
blackjack(19, 21) → 21
blackjack(21, 19) → 21
blackjack(19, 22) → 19
Solution:
public int blackjack(int a, int b) {
int aVal = a > 21 ? 0 : a;
int bVal = b > 21 ? 0 : b;
return aVal>bVal? aVal:bVal;
}
Equivalent to:
public int blackjack(int a, int b) {
// The value of a/b, or 0 if over 21
int aVal = a;
if (aVal > 21) {
aVal = 0;
}
int bVal = b;
if (bVal > 21) {
bVal = 0;
}
// Now it works to just return whichever is larger.
if (aVal > bVal) {
return aVal;
}
else {
return bVal;
}
// You can write a very short version of this same strategy
// using the "ternary operator" ?: and Math.max()
}
