一个字符串 <message>HELLO!</message>
,怎样解析得到HELLO!
?
正则表达式可以轻松解决,但是节点多了就搞不定了。
1、使用JDOM
String xml = "<message>HELLO!</message>";
org.jdom.input.SAXBuilder saxBuilder = new SAXBuilder();
try {
org.jdom.Document doc = saxBuilder.build(new StringReader(xml));
String message = doc.getRootElement().getText();
System.out.println(message);
} catch (JDOMException e) {
// handle JDOMException
} catch (IOException e) {
// handle IOException
}
2、使用Xerces DOMParser
String xml = "<message>HELLO!</message>";
DOMParser parser = new DOMParser();
try {
parser.parse(new InputSource(new java.io.StringReader(xml)));
Document doc = parser.getDocument();
String message = doc.getDocumentElement().getTextContent();
System.out.println(message);
} catch (SAXException e) {
// handle SAXException
} catch (IOException e) {
// handle IOException
}
3、使用 JAXP
String xml = "<message>HELLO!</message>";
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = null;
try {
db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
try {
Document doc = db.parse(is);
String message = doc.getDocumentElement().getTextContent();
System.out.println(message);
} catch (SAXException e) {
// handle SAXException
} catch (IOException e) {
// handle IOException
}
} catch (ParserConfigurationException e1) {
// handle ParserConfigurationException
}
4、使用JAXB
包
import java.io.StringReader;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;
String xmlString = "<message>HELLO!</message> ";
JAXBContext jc = JAXBContext.newInstance(String.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
StreamSource xmlSource = new StreamSource(new StringReader(xmlString));
JAXBElement<String> je = unmarshaller.unmarshal(xmlSource, String.class);
System.out.println(je.getValue());
5、使用jdk自带功能
String msg = "<message>HELLO!</message>";
DocumentBuilder newDocumentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document parse = newDocumentBuilder.parse(new ByteArrayInputStream(msg.getBytes()));
System.out.println(parse.getFirstChild().getTextContent());