丑数

'''
题目：我们把只包含因子2、3和5的数称作丑数。求按从小到大的顺序的第1500个丑数。1为第一个丑数。
'''

def get_ugly_number(count):
    if count <= 0:
        return 0;
    ugly_number_list = [1]
    multiply2 = 0
    multiply3 = 0
    multiply5 = 0
    while len(ugly_number_list) < count:
        m = min((ugly_number_list[multiply2] * 2, ugly_number_list[multiply3] * 3, ugly_number_list[multiply5] * 5))
        ugly_number_list.append(m)
        while ugly_number_list[multiply2] * 2 <= ugly_number_list[-1]:
            multiply2 += 1
        while ugly_number_list[multiply3] * 3 <= ugly_number_list[-1]:
            multiply3 += 1
        while ugly_number_list[multiply5] * 5 <= ugly_number_list[-1]:
            multiply5 += 1
    print ugly_number_list
    return ugly_number_list[-1]
if __name__ == '__main__':

    print get_ugly_number(1500)