如下图，在一维数组中若将含有相同字段属性的归纳，转换为二维数组
- 一维数组
let arr = [
{code: "China", name: "xiaohuai"},
{code: "Africa", name: "neiLuoBi"},
{code: "Asia", name: "hanGuo"},
{code: "China", name: "tnnyang"},
{code: "Africa", name: "nanFei"},
{code: "China", name: "yangMan"}
]
- 二维数组
let arr = [
[ {code: "China", name: "xiaohuai"}, {code: "China", name: "tnnyang"}, {code: "China", name: "yangMan"} ],
[ {code: "Africa", name: "neiLuoBi"}, {code: "Africa", name: "nanFei"} ],
[ {code: "Asia", name: "hanGuo"} ]
]
1. 将一维数组转换成二维数组
let arr = [
{code: "China", name: "xiaohuai"},
{code: "Africa", name: "neiLuoBi"},
{code: "Asia", name: "hanGuo"},
{code: "China", name: "tnnyang"},
{code: "Africa", name: "nanFei"},
{code: "China", name: "yangMan"}
]
// 重点
var map = new Map();
var newArr = [];
arr.forEach(item => {
map.has(item.code) ? map.get(item.code).push(item) : map.set(item.code, [item]);
})
newArr = [...map.values()];
console.log(newArr);
2. 将二维数组转换成一维数组
let arr = [
[ {code: "China", name: "xiaohuai"}, {code: "China", name: "tnnyang"}, {code: "China", name: "yangMan"} ],
[ {code: "Africa", name: "neiLuoBi"}, {code: "Africa", name: "nanFei"} ],
[ {code: "Asia", name: "hanGuo"} ]
]
//方法一：
function reduceDimension(arr) {
var reduced = [];
for (var i = 0; i < arr.length; i++) {
for (var j = 0; j < arr[i].length; j++) {
reduced.push(arr[i][j]);
}
}
return reduced;
}
console.log(reduceDimension(arr));
//方法二：
console.log([].concat.apply([], arr));
方法一是循环遍历，没啥说的。方法二有必要说一下，apply方法会调用一个函数，apply方法的第一个参数会作为被调用函数的this值，apply方法的第二个参数（一个数组，或类数组的对象）会作为被调用对象的arguments值，也就是说该数组的各个元素将会依次成为被调用函数的各个参数
