- 元祖（tuple）：只读
- 列表（list）：增删改查
- 集合（set）：没有重复元素，增删改查
- 字典（dict）
集合(set) 和 字典(dict) 都用{}表示。
#元祖：只读
In [19]: a = (11,22,33,11,22,33)
In [20]: a
Out[20]: (11, 22, 33, 11, 22, 33)
In [21]: type(a)
Out[21]: tuple
#list：增、删、改、查
In [22]: b = [11,22,33,11,22,33]
In [23]: b
Out[23]: [11, 22, 33, 11, 22, 33]
In [24]: type(b)
Out[24]: list
#set：去重
In [25]: c = {11,22,33,11,22,33}
In [26]: c
Out[26]: {11, 22, 33}
In [27]: type(c)
Out[27]: set
#字典
In [25]: d = {"1":"abc", "2":"def"}
In [26]: d
Out[26]: {'2': 'def', '1': 'abc'}
In [27]: type(d)
Out[27]: dict
set 集合：
In [54]: c = {11, 22, 33, 44}
In [53]: c.
c.add c.issubset
c.clear c.issuperset
c.copy c.pop
c.difference c.remove
c.difference_update c.symmetric_difference
c.discard c.symmetric_difference_update
c.intersection c.union
c.intersection_update c.update
c.isdisjoint
In [53]: help(c.add) #查看帮助
Help on built-in function add:
add(...) method of builtins.set instance
Add an element to a set.
This has no effect if the element is already present.
#按q退出帮助
列表去重
方法一：
In [41]: a = [11,22,33,44,22,11,33]
In [42]: b = []
In [45]: for i in a:
....: if i not in b:
....: b.append(i)
....:
In [46]: b
Out[46]: [11, 22, 33, 44]
方法二：
In [28]: a = [11,22,33,44,22,11,33]
In [48]: c = list(set(a))
In [49]: c
Out[49]: [33, 11, 44, 22]
