最近在B站看C++ 课程，发现复制构造函数调用举例 跟自己的调试不一样。以下是代码。

#include <iostream>
using namespace std;
class Point{
    public:
    Point();
    Point(const Point &obj);
    void getPosition();
    private:
    int x,y;
};
Point::Point(){
    cout<<"Calling Constructor "<<endl;
}
Point::Point(const Point &p){
    x = p.x;
    y = p.y;
    cout<<"Calling Copy Constructor "<<endl;
}
void Point::getPosition(){
    cout<<"x "<<x<<" y "<<y<<endl;
}
void fun1(Point p);
Point fun2();
int main(){
    Point a;
    a.getPosition();
    cout<<"\n"<<endl;

    Point c;
    c.getPosition();
    cout<<"\n"<<endl;

    Point b(a);
    b.getPosition();
    cout<<"\n"<<endl;

    fun1(b);
    cout<<"\n"<<endl;

    b = fun2();
    b.getPosition();
    return 0;
}
void fun1(Point p){
    cout<<"Calling fun1 begin"<<endl;
    p.getPosition();
    cout<<"Calling fun1 end"<<endl;
}
Point fun2(){
    cout<<"Calling fun2 begin"<<endl;
    Point b;
    cout<<"Calling fun2 end"<<endl;
    return b;
}

下边是打印结果

Calling Constructor
x -400344992 y 32766
Calling Constructor
x 0 y 0
Calling Copying Constructor
x -400344992 y 32766
Calling Copying Constructor
Calling fun1 begin
x -400344992 y 32766
Calling fun1 end
Calling fun2 begin
Calling Constructor
Calling fun2 end
x 0 y 0

B站的视频说在调用fun2()的时候也会发生复制，但是结果里并没有发生。
是我弄错了？

另一个疑问就是：Point a跟 Point c 初始化顺序不一样，x,y的值也不一样？