[NSURLURLWithString:urlString]生成URL对象时,iOS客户端不能正确进行网络请求,网上找到的URLEncode方法又不能完全解决问题.

方法1:

NSString* encodedString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

方法2:

NSString * encodedString = (NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,(CFStringRef)urlString,NULL,NULL,kCFStringEncodingUTF8);

这两种方法当urlString里含有中文时URL编码是正确的,但是如果其中含有已转义的%等符号时,又会再次转义而导致错误.

查看方法2参数说明:

CFStringRef CFURLCreateStringByAddingPercentEscapes(CFAllocatorRef allocator,CFStringRef originalString, CFStringRef charactersToLeaveUnescaped, CFStringRef legalURLCharactersToBeEscaped,CFStringEncoding encoding);

因此做出修改,写出方法:

NSString *encodedString = (NSString *)

CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,

(CFStringRef)urlString,

(CFStringRef)@"!$&'()*+,-./:;=?@_~%#[]",

NULL,

kCFStringEncodingUTF8);