#统计字符串中的元音总个数
def calculate(source):
a = ["a","e","i","o","u"]
return sum([1 for e in source if str.lower(e) in a])
#统计各个元音的个数
def caculate1(source):
m = {}
a = ["a","e","i","o","u"]
for e in source:
if str.lower(e) in a:
if str.lower(e) in m:
m[str.lower(e)] = m[str.lower(e)] + 1
else:
m[str.lower(e)] = 1
return m
