1、表的字段类型为 DateTime
今天
select * from 表名 where to_days(时间字段名) = to_days(now());
昨天
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1
7天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)
近30天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)
本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1
#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select*from`user`whereDATE_FORMAT(pudate,'%Y%m')=DATE_FORMAT(CURDATE(),'%Y%m') ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select*
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' ))=MONTH (now())
select*
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' ))=YEAR (now())
andMONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' ))=MONTH (now())
select*
from [ user ]
where pudatebetween上月最后一天
and下月第一天
where date(regdate) = curdate();
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30
通过时间戳来判断昨天的数据
select*fromtable_namewhere`time` > (unix_timestamp()-3600*24*1);
如果多计算几天后面1修改为对应的数字就可以了
通过时间戳计算当天的所有数据
$now = strtotime(date('Y-m-d'));
$sql="SELECT *FROM pay WHERE paytime >= $now and paytime < $now+24*3600";
数据表字段时间戳格式计算昨天的所有数据
$now = strtotime(date('Y-m-d'));
$sql="SELECT * FROM pay WHERE paytime >= $now-24*3600 and paytime < $now";
