#! /usr/bin/env python
# -*- coding:utf-8 -*-
# join # '_'.join("asdfasdf")
# split
# find
# strip
# upper
# lower
# replace
###################### 7个常用string ######################
#join以什么连接字符串
# n1 = 'dsada'
# n2 = '_'
# v = n2.join(n1)
# print(v)
# ----------------------
# split分割符 以什么分割，分割成几份
# n1 = 'timetimetime'
# v = n1.split('t' , 3)
# print(v)
# ----------------------
# find 从开始往后找，找到第一个之后，获取其未知
# n1 = 'timetimetime'
# v = n1.find('me')
# print(v)
# ----------------------
# strip 移除左右空白
# n1 = ' timetimetime '
# v = n1.strip()
# print(v)
# ----------------------
# upper小写转换成大写
# n1 = 'timetimeTime'
# v = n1.upper()
# print(v)
# ----------------------
# lower大写转成小写
# n1 = 'timetimeTime'
# v = n1.lower()
# print(v)
# ----------------------
# replace替换字符串(区分大小写)
# n1 = 'timetimeTime'
# v = n1.replace('time' , 'wentian')
# print(v)
###################### 4个灰魔法######################
# for 变量名 in 字符串:
# 变量名
# break
# continue
# text = 'mianshigual'
# for itme in text:
# print(itme)
#索引，下标，获取字符串中的某一个字符
# text = 'mianshigual'
# v = text[3]
# print(v)
#切片 取索引为0-4的字符
# text = 'mianshigual'
# v = text[0:4]
# print(v)
#len 获取长度 len获取当前字符串中由几个字符组成
# text = 'mianshigual'
# v = len(text)
# print(v)
#获取连续或不连续的数字
# Python2中直接创建在内容中
# python3中只有for循环时，才一个一个创建
# r1 = range(10)
# r2 = range(1,10)
# r3 = range(1,10,2)
# 帮助创建连续的数字,通过设置步长来指定不连续
# v = range(0, 100, 5)
#
# for item in v:
# print(item)
# n1 = range(10)
# print(n1)
#
# n2 = range(0 , 10 , 3)
# print(n2)
#
# for itme in n2:
# print(itme)
##### 练习题：根据用户输入的值，输出每一个字符以及当前字符所在的索引位置#####
# n1 = input('>>>>')
# #打印字符串
# for itme in n1:
# print(itme)
#获取字符串的长度
# v = range(0 , len(n1))
#
# for itme in v:
# print(itme , n1[itme]) #打印字符串对应索引
# for itme in range(0 , len(n1)):
# print(itme , n1[itme])
###################### 1个深灰魔法######################
# 字符串一旦创建，不可修改
# 一旦修改或者拼接，都会造成重新生成字符串
# name = "zhengjianwen"
# age = "18"
#
# info = name + age
# print(info)
