题目描述
给定一个 Weather 表，编写一个 SQL 查询，来查找与之前（昨天的）日期相比温度更高的所有日期的 Id。
+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------------+------------------+
例如，根据上述给定的 Weather 表格，返回如下 Id:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
分析
跟昨天的数据连表，连表的条件是SUBDATE(a.RecordDate,1) = b.RecordDate
代码
# Write your MySQL query statement below
SELECT
a.Id
from
Weather a,
Weather b
where
SUBDATE(a.RecordDate, 1) = b.RecordDate and a.Temperature > b.Temperature
;
题目链接
https://leetcode-cn.com/problems/rising-temperature/description/
