c1 : 长度>=8
c2: 包含数字和字母
c3: 其他可见的特殊字符
强：满足c1,c2,c3
中: 只满足任一2个条件
弱：只满足任一1个或0个条件'''
import re,string
#方法1：定义每个条件的标志位
def check_password_level(s):
flag1 = False #长度是否大于8
flag2 = False #是否包含数字
flag3 = False #是否包含字母
flag4 = False #是否包含其它可见字符
result = []
if len(s) >= 8:
flag1 = True
for i in s:
if i.isalpha():
flag3 = True
elif i.isdigit():
flag2 = True
elif i in string.punctuation:
flag4 = True
if flag2 and flag3:
result.append(True)
else:
result.append(False)
result += [flag1,flag4]
#True加法运算相当于1，false相当于0
if sum(result)==3:
print('强')
elif sum(result)==2:
print('中')
else:
print('弱')
check_password_level('123k.')
check_password_level('123.')
check_password_level('~youlo0418')
#方法2：全部用正则
def check_password_level(s):
num = 0
#既有数字又有字母的正则表达式
re_alnum = r'(\d+)([a-zA-Z]+)|([a-zA-Z]+)(\d+)'
re_special_charactor = r"[%s]+"%string.punctuation
if len(s)>=8 :
num += 1
if re.findall(re_alnum,s) :
num += 1
if re.findall(re_special_charactor,s):
num += 1
if num == 3:
print("强")
elif num == 2:
print("中")
else:
print('弱')
check_password_level('~youlo0918')
check_password_level('^youlo@')
check_password_level('201909youlo')
#方法3：正则+filter
def check_password_level(s):
level_dict = {3:"强",2:"中",1:'弱',0:'弱'}
expression = bool(len(s)>=8) +bool(list(filter(lambda x:re.findall(r'(\d+)([a-zA-Z]+)|([a-zA-Z]+)(\d+)',x), [s]))) \
+bool( list(filter(lambda x:re.findall(r"[%s]+"%string.punctuation,x), [s])) )
return level_dict[expression]
check_password_level('~youlo0418')
check_password_level('^youlo@')
check_password_level('201909youlo')
#方法4：string+filter
def check_password_level(s):
level_dict = {3:"强",2:"中",1:'弱',0:'弱'}
expression = bool(len(s)>=8) +bool(list(filter(lambda x: x in string.digits ,s)) and list(filter(lambda x: x in string.ascii_letters ,s))) \
+bool( list(filter(lambda x:x in string.punctuation, s)) )
return level_dict[expression]
check_password_level('~youlo0418')
check_password_level('^youlo@')
check_password_level('201909youlo')
#方法5：
def check_password_level(s):
c1 = len(s)>=8
c2 = re.findall(r'.*[A-Za-z]+.*',s) != [] and re.findall(r'.*\d+.*',s) != []
c3 = False
for i in s:
if i in string.punctuation:
c3 = True
break
if c1 and c2 and c3:
print('强')
elif (c1 and c2) or(c1 and c3) or(c2 and c3):
print('中')
else:
print('弱')
check_password_level('~youlo0418')
check_password_level('^youlo@')
check_password_level('201909youlo')
