lintCode题解(9)

标签（空格分隔）： lintCode

Fizz Buzz 问题

描述:

给你一个整数n. 从 1 到 n 按照下面的规则打印每个数：

如果这个数被3整除，打印fizz.
如果这个数被5整除，打印buzz.
如果这个数能同时被3和5整除，打印fizz buzz.

样例

比如 n = 15, 返回一个字符串数组：

[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]

挑战

Can you do it with only one if statement?

class Solution {
public:
    /**
     * @param n: An integer
     * @return: A list of strings.
     */
    vector<string> fizzBuzz(int n) {
       vector<string> result;
        stringstream ss("");
        string val;
        for (int i = 1; i < n + 1; i++) {
            val = (i % 15 == 0 ? "fizz buzz" : (i % 3 == 0 ? "fizz" : (i % 5 == 0 ? "buzz" : "")));
            if (val.length() == 0) {
                ss.clear();
                ss << i;
                ss >> val;
                ss.str("");
            }
            result.push_back(val);
        }
        return result;
    }
};