标签（空格分隔）： lintCode
Fizz Buzz 问题
描述:
给你一个整数n. 从 1 到 n 按照下面的规则打印每个数：
如果这个数被3整除，打印fizz.
如果这个数被5整除，打印buzz.
如果这个数能同时被3和5整除，打印fizz buzz.
样例
比如 n = 15, 返回一个字符串数组：
[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]
挑战
Can you do it with only one if statement?
class Solution {
public:
/**
* @param n: An integer
* @return: A list of strings.
*/
vector<string> fizzBuzz(int n) {
vector<string> result;
stringstream ss("");
string val;
for (int i = 1; i < n + 1; i++) {
val = (i % 15 == 0 ? "fizz buzz" : (i % 3 == 0 ? "fizz" : (i % 5 == 0 ? "buzz" : "")));
if (val.length() == 0) {
ss.clear();
ss << i;
ss >> val;
ss.str("");
}
result.push_back(val);
}
return result;
}
};
