i++ vs ++i

  • ++i will increment the value of i, and then return the incremented value.
i = 1;
j = ++i;  //i is 2, j is 2

T& T::operator++() // pre-increment, return *this by reference
{
  return *this;
}
  • i++ will increment the value of i, but return the original value that i held before being incremented.
i = 1
j = i++;  //i is 2, j is 1

T T::operator++(int) // post-increment
{
  T copy(*this);
  ++(*this);// pre-increment here seems logical
  return copy;
}

For a for loop, either works, ++i seems more common. There is a couple of comments regarding the efficiency of ++i and i++. In any non-student project compiler, there will be no performance difference.
It's different for a C++ object, since operator++() is a function and the compiler can't know to optimize away the creation of a temporary object to hold the intermediate value.

最后编辑于
©著作权归作者所有,转载或内容合作请联系作者
【社区内容提示】社区部分内容疑似由AI辅助生成,浏览时请结合常识与多方信息审慎甄别。
平台声明:文章内容(如有图片或视频亦包括在内)由作者上传并发布,文章内容仅代表作者本人观点,简书系信息发布平台,仅提供信息存储服务。

相关阅读更多精彩内容

友情链接更多精彩内容