/*
Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
*/
/*
切割字符串,如果长度为1，补足为2
Error:可能会出现多个版本，因此需要根据两个版本中的居多者补齐，然后
输入一个比较函数，比较每一个子版本
*/
func compareVersion(_ version1: String, _ version2: String) -> Int {
var v1Array = version1.components(separatedBy: ".")
var v2Array = version2.components(separatedBy: ".")
let versionLength = max(v1Array.count, v2Array.count)
for _ in 0..<versionLength-v1Array.count {
v1Array.append("0")
}
for _ in 0..<versionLength-v2Array.count {
v2Array.append("0")
}
//如果相等，则继续比较，如果不等，则直接返回结果
func compareResult(_ v1: String, _ v2: String) -> Int {
if Int(v1)! > Int(v2)! {
return 1
}
else if Int(v1)! < Int(v2)! {
return -1
}
else {
return 0
}
}
var result = 0
for i in 0..<versionLength {
let ret = compareResult(v1Array[i], v2Array[i])
if ret != 0 {
result = ret
break
}
}
return result
}
compareVersion("1.0.1", "1")
165. Compare Version Numbers
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