LeetCode 205 Isomorphic Strings
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Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg" , "add", return true.
Given "foo", "bar", return false.
Given "paper", "title", return true.
Note:
You may assume both s and t have the same length.
判断两个字符串是否同构，要点在于，字符串S1与S2中的字符只能一一对应，如果用两个map记录相互对应关系，S1中的字符a对应S2中的字符b可以表示为map1：<a,b>与map2：<b,a>，当S1再次出现a时，S2对应位置一定是map1中的b；而当S1中出现c时，map2中一定不含有key：c。
代码如下：
public class Solution {
public boolean isIsomorphic(String s, String t) {
HashMap<Character,Character> m1 = new HashMap<Character,Character>();
HashMap<Character,Character> m2 = new HashMap<Character,Character>();
for (int i = 0; i < s.length(); i++) {
if (!m1.containsKey(s.charAt(i))) {
if (m2.containsKey(t.charAt(i))) return false;
m1.put(s.charAt(i), t.charAt(i));
m2.put(t.charAt(i), s.charAt(i));
} else {
if (m1.get(s.charAt(i)) != t.charAt(i)) return false;
}
}
return true;
}
}
