有时需求会是从后端获取url然后拼接字符再请求，这里会需要对未知NSString进行去除空格换行等操作，否则NSUrl会是nil！
NSString *url = @"www.baidu.co m";//后端获取得到（里面带有空格换行等）
NSString *name = @"小明";
//中文转编码
NSString *nameCode = [name stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
//拼接
NSString *urlStr = [NSString stringWithFormat:@"%@&name=%@",url,nameCode];
//去除空格和换行
urlStr = [urlStr stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
urlStr = [urlStr stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
urlStr = [urlStr stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
urlStr = [urlStr stringByReplacingOccurrencesOfString:@"\r" withString:@""];
urlStr = [urlStr stringByReplacingOccurrencesOfString:@"\n" withString:@""];
NSURL *urlU = [NSURL URLWithString:urlStr];
NSURLRequest *request = [NSURLRequest requestWithURL:urlU];
[self.currentWebView loadRequest:request];
更新：推荐使用该方法对url进行中文转译，不管中文内容在字符串任何位置。
payUrlStr = (NSString *)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)payUrlStr, (CFStringRef)@"!NULL,'()*+,-./:;=?@_~%#[]", NULL, kCFStringEncodingUTF8));
