Validate if a given string is numeric.
Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true
Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.
Solution:check
思路:
Time Complexity: O(N) Space Complexity: O(1)
Solution Code:
class Solution {
public boolean isNumber(String s) {
// eliminates leading and trailing spaces
s = s.trim();
boolean pointSeen = false;
boolean eSeen = false;
boolean numberSeen = false;
boolean numberAfterE = true;
for(int i=0; i<s.length(); i++) {
if(Character.isDigit(s.charAt(i))) {
numberSeen = true;
numberAfterE = true;
} else if(s.charAt(i) == '.') {
if(eSeen || pointSeen) {
return false;
}
pointSeen = true;
} else if(s.charAt(i) == 'e') {
if(eSeen || !numberSeen) {
return false;
}
numberAfterE = false;
eSeen = true;
} else if(s.charAt(i) == '-' || s.charAt(i) == '+') {
if(i != 0 && s.charAt(i-1) != 'e') {
return false;
}
} else {
return false;
}
}
return numberSeen && numberAfterE;
}
}
test case
test(1, "123", true);
test(2, " 123 ", true);
test(3, "0", true);
test(4, "0123", true); //Cannot agree
test(5, "00", true); //Cannot agree
test(6, "-10", true);
test(7, "-0", true);
test(8, "123.5", true);
test(9, "123.000000", true);
test(10, "-500.777", true);
test(11, "0.0000001", true);
test(12, "0.00000", true);
test(13, "0.", true); //Cannot be more disagree!!!
test(14, "00.5", true); //Strongly cannot agree
test(15, "123e1", true);
test(16, "1.23e10", true);
test(17, "0.5e-10", true);
test(18, "1.0e4.5", false);
test(19, "0.5e04", true);
test(20, "12 3", false);
test(21, "1a3", false);
test(22, "", false);
test(23, " ", false);
test(24, null, false);
test(25, ".1", true); //Ok, if you say so
test(26, ".", false);
test(27, "2e0", true); //Really?!
test(28, "+.8", true);
test(29, " 005047e+6", true); //Damn = =|||