题目
{920139713,19}
704796792
752211152
274704164
18414022
368270835
483295235
263072905
459788476
483295235
459788476
663551792
475206804
459788476
428313374
475206804
459788476
425392137
704796792
458265677
341524652
483295235
534149509
425392137
428313374
425392137
341524652
458265677
263072905
483295235
828509797
341524652
425392137
475206804
428313374
483295235
475206804
459788476
306220148
1 分解n
http://www.factordb.com/index.php?query=920139713
http://www.atool.org/quality_factor.php
或者
import libnum
libnum.factorial(920139713)
2 求d
from gmpy2 import *
p = mpz(18443)
q = mpz(49891)
e = mpz(19)
l = (p-1)*(q-1)
d = invert(e, l)
print("d is ", d)
3 脱密
把题中的n和e去掉，保存成文本rsa.txt
n = 920139713
d = 96849619
result = []
with open('rsa.txt') as f:
for i in f:
result.append(chr(pow(int(i), d, n)))
得到
'flag{13212je2ue28fy71w8u87y31r78eu1e2}'
