Determine whether an integer is a palindrome. Do this without extra space.

Python

class Solution(object):
    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """
        if x < 0:
            return bool(0)
        x_str = str(x)
        if len(x_str) % 2 == 0:
            if x_str[:len(x_str)/2] == x_str[:len(x_str)/2 - 1:-1]:
                return bool(1)
            else:
                return bool(0)
        else:
            if x_str[:len(x_str)/2] == x_str[:len(x_str)/2:-1]:
                return bool(1)
            else:
                return bool(0)

Java

class Solution {
    public boolean isPalindrome(int x) {
        char[] x_char= String.valueOf(x).toCharArray();
        boolean result = true;
        for(int i = 0, j = x_char.length - 1; i <= x_char.length && j >= i; i ++, j--){
            if (x_char[i] != x_char[j]) {
                result = false;
                return result;
            }
        }
        return result;
    }
}