package chapter_4_recursionanddp;
public class Problem_01_FibonacciProblem {
public static int f1(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2) {
return 1;
}
return f1(n - 1) + f1(n - 2);
}
public static int f2(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2) {
return 1;
}
int res = 1;
int pre = 1;
int tmp = 0;
for (int i = 3; i <= n; i++) {
tmp = res;
res = res + pre;
pre = tmp;
}
return res;
}
public static int f3(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2) {
return 1;
}
int[][] base = { { 1, 1 }, { 1, 0 } };
int[][] res = matrixPower(base, n - 2);
return res[0][0] + res[1][0];
}
public static int[][] matrixPower(int[][] m, int p) {
int[][] res = new int[m.length][m[0].length];
// 先把res设为单位矩阵,相等于整数中的1。
for (int i = 0; i < res.length; i++) {
res[i][i] = 1;
}
int[][] tmp = m;
for (; p != 0; p >>= 1) {
if ((p & 1) != 0) {
res = muliMatrix(res, tmp);
}
tmp = muliMatrix(tmp, tmp);
}
return res;
}
public static int[][] muliMatrix(int[][] m1, int[][] m2) {
int[][] res = new int[m1.length][m2[0].length];
for (int i = 0; i < m1.length; i++) {
for (int j = 0; j < m2[0].length; j++) {
for (int k = 0; k < m2.length; k++) {
res[i][j] += m1[i][k] * m2[k][j];
}
}
}
return res;
}
public static int s1(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2) {
return n;
}
return s1(n - 1) + s1(n - 2);
}
public static int s2(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2) {
return n;
}
int res = 2;
int pre = 1;
int tmp = 0;
for (int i = 3; i <= n; i++) {
tmp = res;
res = res + pre;
pre = tmp;
}
return res;
}
public static int s3(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2) {
return n;
}
int[][] base = { { 1, 1 }, { 1, 0 } };
int[][] res = matrixPower(base, n - 2);
return 2 * res[0][0] + res[1][0];
}
public static int c1(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2 || n == 3) {
return n;
}
return c1(n - 1) + c1(n - 3);
}
public static int c2(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2 || n == 3) {
return n;
}
int res = 3;
int pre = 2;
int prepre = 1;
int tmp1 = 0;
int tmp2 = 0;
for (int i = 4; i <= n; i++) {
tmp1 = res;
tmp2 = pre;
res = res + prepre;
pre = tmp1;
prepre = tmp2;
}
return res;
}
public static int c3(int n) {
if (n < 1) {
return 0;
}
if (n == 1 || n == 2 || n == 3) {
return n;
}
int[][] base = { { 1, 1, 0 }, { 0, 0, 1 }, { 1, 0, 0 } };
int[][] res = matrixPower(base, n - 3);
return 3 * res[0][0] + 2 * res[1][0] + res[2][0];
}
public static void main(String[] args) {
int n = 20;
System.out.println(f1(n));
System.out.println(f2(n));
System.out.println(f3(n));
System.out.println("===");
System.out.println(s1(n));
System.out.println(s2(n));
System.out.println(s3(n));
System.out.println("===");
System.out.println(c1(n));
System.out.println(c2(n));
System.out.println(c3(n));
System.out.println("===");
}
}
Problem_01_FibonacciProblem
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【社区内容提示】社区部分内容疑似由AI辅助生成,浏览时请结合常识与多方信息审慎甄别。
平台声明:文章内容(如有图片或视频亦包括在内)由作者上传并发布,文章内容仅代表作者本人观点,简书系信息发布平台,仅提供信息存储服务。
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