拼接url参数字符串(复杂obj)

定义函数

encodeSearchParams(obj, parentObj) {
      // Object.keys(obj).forEach((key) => {
      for (let key in obj) {
        let value = obj[key]
        let t = typeof value
        // 如果值为undefined我们将其置空
        if (t === 'undefined') {
          value = ''
        } else if (t === 'string' || t === 'number' || t === 'boolean') {
          if (parentObj) {
            this.params = this.params + '&' + parentObj + '[' + key + ']' + '=' + value
          } else {
            this.params = this.params + '&' + key + '=' + value
          }
          continue
        } else {
          this.encodeSearchParams(value, key)
        }
      }
      return this.params
    }

调用

 this.encodeSearchParams(obj)