问题描述
Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not.
You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.
思路
recursive
把第二棵树的值,直接加到第一棵树上,或者重新创建一棵树
class Solution(object):
def mergeTrees(self, t1, t2):
"""
:type t1: TreeNode
:type t2: TreeNode
:rtype: TreeNode
"""
if not t1 and not t2: return None
if not t1: return t2
if not t2: return t1
t1.val += t2.val
t1.left = self.mergeTrees(t1.left, t2.left)
t1.right = self.mergeTrees(t1.right, t2.right)
return t1
class Solution(object):
def mergeTrees(self, t1, t2):
"""
:type t1: TreeNode
:type t2: TreeNode
:rtype: TreeNode
"""
if not t1 and not t2: return None
ans = TreeNode((t1.val if t1 else 0) + (t2.val if t2 else 0))
ans.left = self.mergeTrees(t1.left, t2.left)
ans.right = self.mergeTrees(t1.right, t2.right)
return ans