题目

这是大城市的奖励时间！胖子正在期待摩擦他们的爪子......但是谁会赚到最多钱？

构建一个包含两个参数（工资，奖金）的函数。工资将是一个整数，并加上一个布尔值。

如果奖金是真的，薪水应该乘以10.如果奖金是假的，胖子没有赚到足够的钱，必须只收到他说的工资。

返回个人将收到的总数字作为前缀为“£”（= "\u00A3"，JS和Java）或“$”（C＃，C ++，Ruby，Clojure，Elixir，PHP和Python，Haskell）的字符串。

测试用例：

import org.junit.Test;
import static org.junit.Assert.assertEquals;
import org.junit.runners.JUnit4;


public class BonusTimeTest {
    @Test
    public void basicTests() {
      boolean wellConfigured=unicodeTest();
      assertEquals((wellConfigured?"£":"\u00A3")+"100000",Kata.bonusTime(10000, true));
      assertEquals((wellConfigured?"£":"\u00A3")+"250000",Kata.bonusTime(25000, true));
      assertEquals((wellConfigured?"£":"\u00A3")+"10000",Kata.bonusTime(10000, false));
      assertEquals((wellConfigured?"£":"\u00A3")+"60000",Kata.bonusTime(60000, false));
      assertEquals((wellConfigured?"£":"\u00A3")+"20",Kata.bonusTime(2, true));
      assertEquals((wellConfigured?"£":"\u00A3")+"78",Kata.bonusTime(78, false));
      assertEquals((wellConfigured?"£":"\u00A3")+"678900",Kata.bonusTime(67890, true));
    }
    
    public boolean unicodeTest(){
      System.out.println("\u00A3 == £:"+"\u00A3".equalsIgnoreCase("£"));
      System.out.println("if previous result was false or had ? symbol then perhaps you need to escape unicode due to misconfiguration");
      return "\u00A3".equalsIgnoreCase("£");
    }
}

解题

My

public class Kata{
  public static String bonusTime(final int salary, final boolean bonus) {
    return "£"+String.valueOf(bonus ? salary*10 : salary);
  }
}

Other

public class Kata{
  public static String bonusTime(final int salary, final boolean bonus) {
    return "\u00A3" + (bonus ? 10 : 1) * salary;
  }
}

后记

看到别人的代码就知道我不懂出题者呀。