1.递归实现
let [a,b,c] = [
[1,2,3,[3,4,5,[5,6,7]]],
["a","b",["c","d",["aa","bb"]]],
["aaaa","bbbb"]
],
//递归实现单个数组的多维转一维
arrCat = a => a.reduce((p,c)=> p.concat(Array.isArray(c)?arrCat(c):c),[]),
//es6扩展运算符
arr= [...arrCat(a),...arrCat(b),...arrCat(c)]
console.log(arr);
//[1, 2, 3, 3, 4, 5, 5, 6, 7, "a", "b", "c", "d", "aa", "bb", "aaaa", "bbbb"]
用forEach和reduce做一个简单的封装joinArr()函数显示数组的合并
let joinArr = (...arr)=> {
let newArr = [];
// [...arr].forEach(item=>{
// newArr.push(...arrCat(item))
// })
// return newArr
return [...arr].reduce((p,c)=>{
return p.concat(arrCat(c))
},[])
}
console.log(joinArr(a, b, c));
//[1, 2, 3, 3, 4, 5, 5, 6, 7, "a", "b", "c", "d", "aa", "bb", "aaaa", "bbbb"]
2.补充
let [a,b,c] = [
[1,2,3,[3,4,5,[5,6,7]]],
["a","b",["c","d",["aa","bb"]]],
["aaaa","bbbb"]
],
k=[...a,...b,...c].toString().split(",");
//字符串数字转成数字
k=k.map(item=>{
if (!isNaN(item-0)) return item-0
return item
})
console.log(k);
//[1, 2, 3, 3, 4, 5, 5, 6, 7, "a", "b", "c", "d", "aa", "bb", "aaaa", "bbbb"]
完善：封装成joinArr()函数
let [a,b,c] = [
[1,2,3,[3,4,5,[5,6,7]]],
["a","b",["c","d",["aa","bb"]]],
["aaaa","bbbb"]
],
joinArr = (...k) =>{
let newArr =[...k].toString().split(",").map(item=>{
if (!isNaN(item-0)) return item-0
return item
})
return newArr
}
console.log(joinArr(a, b, c));
