Task4 建模调参

sample_feature = sample_feature.dropna().replace('-', 0).reset_index(drop=True)

1.读取数据

reduce_mem_usage 函数根据每列数据所在的范围,调整数据类型,减少数据在内存中占用的空间

>>> np.iinfo(np.int) # Bounds of the default integer on this system.
iinfo(min=-9223372036854775808, max=9223372036854775807, dtype=int64)

2.建模

# 去掉含有缺失值的行;drop=true,原行索引删除;['notRepairedDamage']一列用0把替换'-';
sample_feature = sample_feature.dropna().replace('-', 0).reset_index(drop=True)
sample_feature['notRepairedDamage'] = sample_feature['notRepairedDamage'].astype(np.float32)
train = sample_feature[continuous_feature_names + ['price']]

train_X = train[continuous_feature_names]
train_y = train['price']

2.1 简单建模

from sklearn.linear_model import LinearRegression
model = LinearRegression(normalize=True)
model = model.fit(train_X, train_y)

查看训练的线性回归模型的截距(intercept)与权重(coef)(不知道有有什么意义)

print('intercept:'+ str(model.intercept_))

# dict(zip())用于构建一个字典
sorted(dict(zip(continuous_feature_names, model.coef_)).items(), key=lambda x:x[1], reverse=True)

绘制特征v_9的值与标签的散点图,图片发现模型的预测结果(蓝色点)与真实标签(黑色点)的分布差异较大,且部分预测值出现了小于0的情况,说明模型存在一些问题

from matplotlib import pyplot as plt
# 取50个点
subsample_index = np.random.randint(low=0, high=len(train_y), size=50)
plt.scatter(train_X['v_9'][subsample_index], train_y[subsample_index], color='black')
plt.scatter(train_X['v_9'][subsample_index], model.predict(train_X.loc[subsample_index]), color='blue')
plt.xlabel('v_9')
plt.ylabel('price')
plt.legend(['True Price','Predicted Price'],loc='upper right')
print('The predicted price is obvious different from true price')
plt.show()

通过作图我们发现数据的标签(price)呈现长尾分布,不利于我们的建模预测。原因是很多模型都假设数据误差项符合正态分布,而长尾分布的数据违背了这一假设。参考博客:https://blog.csdn.net/Noob_daniel/article/details/76087829

import seaborn as sns
print('It is clear to see the price shows a typical exponential distribution')
plt.figure(figsize=(15,5))
plt.subplot(1,2,1)
sns.distplot(train_y)
plt.subplot(1,2,2)
# 画出90%的数据
sns.distplot(train_y[train_y < np.quantile(train_y, 0.9)])

在这里我们对标签进行了log(x+1) 变换,使标签贴近于正态分布
再次进行可视化,发现预测结果与真实值较为接近,且未出现异常状况

2.2五折交叉验证

通过make_scorer构建一个完整的定制scorer函数
https://www.cnblogs.com/harvey888/p/6964741.html

from sklearn.model_selection import cross_val_score
from sklearn.metrics import mean_absolute_error,  make_scorer
def log_transfer(func):
    def wrapper(y, yhat):
        result = func(np.log(y), np.nan_to_num(np.log(yhat)))
        return result
    return wrapper
#使用线性回归模型,对未处理标签的特征数据进行五折交叉验证(Error 1.36)
scores = cross_val_score(model, X=train_X, y=train_y, verbose=1, cv = 5, scoring=make_scorer(log_transfer(mean_absolute_error)))
# 使用线性回归模型,对处理过标签的特征数据进行五折交叉验证(Error 0.19)
scores = cross_val_score(model, X=train_X, y=train_y_ln, verbose=1, cv = 5, scoring=make_scorer(mean_absolute_error))

2.3模拟真实业务情况

事实上,由于我们并不具有预知未来的能力,五折交叉验证在某些与时间相关的数据集上反而反映了不真实的情况。通过2018年的二手车价格预测2017年的二手车价格,这显然是不合理的,因此我们还可以采用时间顺序对数据集进行分隔。在本例中,我们选用靠前时间的4/5样本当作训练集,靠后时间的1/5当作验证集,最终结果与五折交叉验证差距不大

sample_feature = sample_feature.reset_index(drop=True)
split_point = len(sample_feature) // 5 * 4
train = sample_feature.loc[:split_point].dropna()
val = sample_feature.loc[split_point:].dropna()
train_X = train[continuous_feature_names]
train_y_ln = np.log(train['price'] + 1)
val_X = val[continuous_feature_names]
val_y_ln = np.log(val['price'] + 1)
model = model.fit(train_X, train_y_ln)
mean_absolute_error(val_y_ln, model.predict(val_X))

2.4绘制学习率曲线与验证曲线

3多种模型对比

train = sample_feature[continuous_feature_names + ['price']].dropna()

train_X = train[continuous_feature_names]
train_y = train['price']
train_y_ln = np.log(train_y + 1)

4模型调参

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