给定三个字符串 s1, s2, s3, 验证 s3 是否是由 s1 和 s2 交错组成的。
示例 1:
输入: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac"
输出: true
示例 2:
输入: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc"
输出: false
代码
class Solution {
public:
bool isInterleave(string s1, string s2, string s3) {
if (s1.size() + s2.size() != s3.size()) return false;
int n1 = s1.size();
int n2 = s2.size();
vector<vector<bool> > dp(n1 + 1, vector<bool> (n2 + 1, false));
dp[0][0] = true;
for (int i = 1; i <= n1; ++i) {
dp[i][0] = dp[i - 1][0] && (s1[i - 1] == s3[i - 1]);
}
for (int i = 1; i <= n2; ++i) {
dp[0][i] = dp[0][i - 1] && (s2[i - 1] == s3[i - 1]);
}
for (int i = 1; i <= n1; ++i) {
for (int j = 1; j <= n2; ++j) {
dp[i][j] = (dp[i - 1][j] && s1[i - 1] == s3[i - 1 + j]) || (dp[i][j - 1] && s2[j - 1] == s3[j - 1 + i]);
}
}
return dp[n1][n2];
}
};
