题目：转圈打印矩阵
给定一个整型矩阵matrix， 请按照转圈的方式打印它。
例如：
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
打印结果为： 1， 2， 3， 4， 8， 12， 16， 15， 14， 13， 9， 5， 6， 7， 11，
10
思路：要以一个整体的思想去看待这个问题
public static void spiralOrderPrint(int[][] matrix) {
int tR = 0;
int tC = 0;
int dR = matrix.length - 1;
int dC = matrix[0].length - 1;
while (tR <= dR && tC <= dC) {
printEdge(matrix, tR++, tC++, dR--, dC--);
}
}
public static void printEdge(int[][] m, int tR, int tC, int dR, int dC) {
if (tR == dR) {
for (int i = tC; i <= dC; i++) {
System.out.print(m[tR][i] + " ");
}
} else if (tC == dC) {
for (int i = tR; i <= dR; i++) {
System.out.print(m[i][tC] + " ");
}
} else {
int curC = tC;
int curR = tR;
while (curC != dC) {
System.out.print(m[tR][curC] + " ");
curC++;
}
while (curR != dR) {
System.out.print(m[curR][dC] + " ");
curR++;
}
while (curC != tC) {
System.out.print(m[dR][curC] + " ");
curC--;
}
while (curR != tR) {
System.out.print(m[curR][tC] + " ");
curR--;
}
}
}
