Given an array of ints, return true if the value 3 appears in the array exactly 3 times, and no 3's are next to each other.
haveThree([3, 1, 3, 1, 3]) → true
haveThree([3, 1, 3, 3]) → false
haveThree([3, 4, 3, 3, 4]) → false

Solution1:

public boolean haveThree(int[] nums) {
  boolean lastIs3 = false;
  int count = 0;
  for(int i=0; i<nums.length; i++ ) {
    if(nums[i]==3 ) {
      if(lastIs3) {
        return false;
      }
      lastIs3 = true;
      count++;
    } else {
      lastIs3 = false;
    }
  }
  if(count == 3) {
    return true;
  }
  return false;
}

Solution2:

public boolean haveThree(int[] nums) {
  String num = Arrays.toString(nums);
  if(!num.contains("3, 3") && count3(nums) == 3 ){
    return true;
  }
  return false;
}
public int count3 (int[] nums) {
  int count = 0;
  for (int val:nums) {
    if(val == 3) {
      count++;
    }
  }
  return count;
}