net：高德地图

//实现正向地理编码的回调函数

• (void)onGeocodeSearchDone:(AMapGeocodeSearchRequest *)request response:(AMapGeocodeSearchResponse *)response
  {
  if(response.geocodes.count == 0)
  {
  return;
  }

  //通过AMapGeocodeSearchResponse对象处理搜索结果
  NSString *strCount = [NSString stringWithFormat:@"count: %d", response.count];
  NSString *strGeocodes = @"";
  for (AMapTip *p in response.geocodes) {
  strGeocodes = [NSString stringWithFormat:@"%@\ngeocode: %@", strGeocodes, p.description];
  }
  NSString *result = [NSString stringWithFormat:@"%@ \n %@", strCount, strGeocodes];
  NSLog(@"Geocode: %@", result);
  }

这句代码。似乎不太合适。
for (AMapTip *p in response.geocodes) {
怎么解？？

1000Phone の Swift 版：
func onGeocodeSearchDone(request: AMapGeocodeSearchRequest!, response: AMapGeocodeSearchResponse!) {

    for p in response.geocodes {
        
        let tip = p as! AMapGeocode
        
        print("\(tip.location.latitude), \(tip.location.longitude)")
        
    }
    
}