This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes

问题链接(https://vjudge.net/problem/HDU-2101)

问题简述：输入A,B值，对A+B的结果进行判断。如果(A+B)%86=0，则输出yes，否则就输出no。

问题分析：这是简单的一道对If语句的一个考查。本程序运用if语句对输入的A B值直接进行判断。

AC通过的C++语言如下

#include<iostream>
using namespace std;
int main()
{
    int A, B;
    while (cin >> A >> B)
    {
        if ((A + B) % 86 == 0)
        {
            cout << "yes" << endl;
        }
        else cout << "no" << endl;
    }
    return 0;
}