1、数据表
CREATE TABLE map_group_ac (
gp_id integer,
ac_id varchar,
PRIMARY KEY(gp_id, ac_id)
);
- 正确的查询语句-SQL是:
NSMutableString *fieldString = [NSMutableString new];
[fieldString appendString:@"SELECT ac_id FROM map_group_ac where gp_id IN ("];
for (NSNumber *gpNoin groups) {
[fieldString appendString:@"?,"];
}
[fieldString replaceCharactersInRange:NSMakeRange([fieldString length] -1,1)withString:@")"];
NSString *normalString = [NSString stringWithString:fieldString];
FMResultSet *ps = [shareDataBase executeQuery:normalString withArgumentsInArray:groups]; //groups is Number Array
3、（3.1-3.3）下面这几种方法试了都不起作用。3.4还未尝试
3.1
NSArray *mergeIds; // An array of NSNumber Objects
NSString *mergeIdString = [mergeIds componentsJoinedByString:@","];
NSString *query = @"SELECT * FROM items WHERE last_merge_id IN (?)";
FMResultSet *res = [self.database executeQueryWithFormat:query, mergeIdString];
3.2
FMResultSet *ps = [shareDataBase executeQuery: @"SELECT ac_id FROM map_group_ac where gp_id in ?", groups];
3.3
NSArray *array = [NSArray arrayWithObjects:@"1",@"2",@"3",nil];
NSString *components = [array componentsJoinedByString:@", "];
NSMutableString *valueString = [NSMutableString new];
NSMutableString *fieldString = [NSMutableString new];[fieldString appendString:@"SELECT id FROM FriendList WHERE id NOT IN ("];
for (NSString *fielValue in array) {
[fieldString appendString:@"?,"];
[valueString appendString:fielValue];
}
[fieldString replaceCharactersInRange:NSMakeRange([fieldString length] - 1, 1) withString:@")"];
NSString *normalString = [NSString stringWithString:fieldString];
FMResultSet * rs = [self.db executeQuery:@"%@", normalString, components];
3.4
https://github.com/mehlkelm/FMDB-InOperator
本文转载自: http://blog.csdn.net/wengyupeng/article/details/60323352
