问题描述
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
思路
去掉空的情况
把str劈开，求最后一个元素的长度
def lengthOfLastWord(self, s):
"""
:type s: str
:rtype: int
"""
if not s:
return 0
elif s.strip()=='':
return 0
else:
return len(s.split()[-1])